1+49x^2=226

Solution for 1+49x^2=226 equation:

1+49x^2=226

We move all terms to the left:

1+49x^2-(226)=0

We add all the numbers together, and all the variables

49x^2-225=0

a = 49; b = 0; c = -225;
Δ = b2-4ac
Δ = 02-4·49·(-225)
Δ = 44100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{44100}=210$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-210}{2*49}=\frac{-210}{98}
=-2+1/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+210}{2*49}=\frac{210}{98}
=2+1/7
$